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Ex 9.3
Ex 9.3, 2 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 3 Deleted for CBSE Board 2023 Exams
Ex 9.3, 4 Deleted for CBSE Board 2023 Exams
Ex 9.3, 5 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 6 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 7 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 8 Deleted for CBSE Board 2023 Exams
Ex 9.3, 9 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 10 Deleted for CBSE Board 2023 Exams
Ex 9.3, 11 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 12 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 13 Deleted for CBSE Board 2023 Exams
Ex 9.3, 14 Deleted for CBSE Board 2023 Exams
Ex 9.3, 15 Deleted for CBSE Board 2023 Exams You are here
Ex 9.3, 16 Important Deleted for CBSE Board 2023 Exams
Last updated at March 22, 2023 by Teachoo
Ex 9.3, 15 Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(AOD) = ar(BOC). Prove that ABCD is a trapezium . Given: A quadrilateral ABCD where diagonals AC & BD intersect at O & ar(AOD) = ar(BOC) To prove: ABCD is a trapezium Proof : A trapezium is a quadrilateral with one pair of opposite sides parallel Given ar(AOD) = ar(BOC) Adding ar (ODC) on both sides, Ar(AOD) + ar(ODC) = ar(BOC) + ar(ODC) ⇒ ar(ADC) = ar(BDC) Now, ΔADC and ΔBDC lie on the same base DC and are equal in area & they lie between the lines AB & DC, ⇒ AB ∥ DC In ABCD, AB ∥ DC So, one pair of opposite sides is parallel, ∴ ABCD is a trapezium Hence proved