1. Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
  2. Serial order wise
  3. Ex 9.3

Ex 9.3, 7 - Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)

Last updated at May 29, 2018 by

Ex 9.3, 7 - D and E are points on sides AB and AC of ABC - Ex 9.3

  1. Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
  2. Serial order wise

    3. Ex 9.3

    Examples →

Transcript

Ex 9.3, 7 D and E are points on sides AB and AC respectively of ABC such that ar (DBC) = ar (EBC). Prove that DE BC. Given: ABC where D and E are points on sides AB and AC such that ar (DBC) = ar (EBC) To prove: DE BC Proof : DBC and EBC are lying on a common base BC and have equal areas, & they lie between the lines DE and BC. So, DE BC Hence proved

Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
Serial order wise

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