Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Jan. 23, 2020 by Teachoo

Transcript

Ex 4.5, 17 (Method 1) Let A be a nonsingular square matrix of order 3 ร 3. Then |adj A| is equal to A. |A| B. |A|2 C. |A|3 D. 3 |A| We know that |๐๐๐ ๐ด| = |๐ด|^(๐ โ 1) where n is the order of Matrix A Here, n = 3 |๐๐๐ ๐ด| = |๐ด|^(3 โ 1) = |๐ด|^2 Hence, B is the correct answer Nonsingular: Where |๐ด|โ 0 Ex 4.5, 17 (Method 2) Let A be a nonsingular square matrix of order 3 ร 3. Then |adj A| is equal to A. |A| B. |A|2 C. |A|3 D. 3 |A| We know that A (adj A) = |A|I Taking determinants both sides |A (ad jA)| = ||A|I| Solving |A (adj (A))| |A (adj (A))| = |A| |adj (A)| (|๐ด๐ต|=|๐ด||๐ต|) Solving ||A|I| ||A|I| = |A|3|I| = |A|3 Now, |A (ad jA)| = ||A|I| Putting values |A| |adj (A)| = |A|3 |adj (A)| = |A|3/|A| |adj (A)| = |A|2 Thus, B is the correct answer Since |A| is Constant Using Property |kA| = kn |A| where n is order of A

Chapter 4 Class 12 Determinants

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.