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  1. Chapter 4 Class 12 Determinants
  2. Serial order wise

Transcript

Ex 4.5, 17 (Method 1) Let A be a nonsingular square matrix of order 3 ร— 3. Then |adj A| is equal to A. |A| B. |A|2 C. |A|3 D. 3 |A| We know that |๐‘Ž๐‘‘๐‘— ๐ด| = |๐ด|^(๐‘› โˆ’ 1) where n is the order of Matrix A Here, n = 3 |๐‘Ž๐‘‘๐‘— ๐ด| = |๐ด|^(3 โˆ’ 1) = |๐ด|^2 Hence, B is the correct answer Nonsingular: Where |๐ด|โ‰  0 Ex 4.5, 17 (Method 2) Let A be a nonsingular square matrix of order 3 ร— 3. Then |adj A| is equal to A. |A| B. |A|2 C. |A|3 D. 3 |A| We know that A (adj A) = |A|I Taking determinants both sides |A (ad jA)| = ||A|I| Solving |A (adj (A))| |A (adj (A))| = |A| |adj (A)| (|๐ด๐ต|=|๐ด||๐ต|) Solving ||A|I| ||A|I| = |A|3|I| = |A|3 Now, |A (ad jA)| = ||A|I| Putting values |A| |adj (A)| = |A|3 |adj (A)| = |A|3/|A| |adj (A)| = |A|2 Thus, B is the correct answer Since |A| is Constant Using Property |kA| = kn |A| where n is order of A

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.