Check sibling questions

Slide46.JPG

Slide47.JPG


Transcript

Ex 4.3,1 Find area of the triangle with vertices at the point given in each of the following: (1, 0), (6, 0), (4, 3) The area of triangle is given by ∆ = 𝟏/𝟐 |■8(𝐱𝟏&𝐲𝟏&𝟏@𝐱𝟐&𝐲𝟐&𝟏@𝐱𝟑&𝐲𝟑&𝟏)| Here, x1 = 1 , y1 = 0 x2 = 6 ,y2 = 0 x3 = 4 ,y3 = 3 ∆ = 𝟏/𝟐 |■8(𝟏&𝟎&𝟏@𝟔&𝟎&𝟏@𝟒&𝟑&𝟏)| = 1/2 (1|■8(0&[email protected]&1)|−0|■8(6&[email protected]&1)|+1|■8(6&[email protected]&3)|) = 1/2 (1(0 – 3) – 0(6 – 4) + 1 (18 – 0)) = 1/2 (1(–3) + 0 + 1 (18) ) = 1/2 [–3 + 18 ] = 𝟏𝟓/𝟐 Thus, the required area of triangle is 𝟏𝟓/𝟐 square units

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.