Manjit wants to donate a rectangular plot of land for a school in his village. When he was asked to give dimensions of the plot, he told that if its length is decreased by 50 m and breadth is increased by 50m, then its area will remain same, but if length is decreased by 10m & breadth is decreased by 20m, then area will decrease by 5300 m 2
Manjit Wants to Donate a Rectungler - Teachoo.jpg


Based on the information given above, answer the following questions:

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Question 1

The equations in terms of X and Y are

(a) x – y = 50, 2x – y = 550

(b) x – y = 50, 2x + y = 550

(c) x + y = 50, 2x + y = 550

(d) x + y = 50, 2x + y = 550

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Question 2

Which of the following matrix equation is represented by the given information

(a) [1 -1] [2 1] [x y] = [50 550] 

(b) [1 1] [2 1] [x y] = [50 550] 

(c) [1 1] [2 -1] [x y] = [50 550]

(d) [1 -2] [2 1] [x y] = [-50 -550] 

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Question 3

The value of x (length of rectangular field) is

(a) 150 m

(b) 400 m

(c) 200 m

(d) 320 m

 

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Question 4

The value of y (breadth of rectangular field) is

(a) 150m

(b) 200m

(c) 430m

(d) 350m

 

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Question 5

How much is the area of rectangular field?

(a) 60000 sq. m.

(b) 30000 sq. m.

(c) 30000 m

(d) 3000 m

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  1. Chapter 4 Class 12 Determinants (Term 1)
  2. Serial order wise

Transcript

Question Manjit wants to donate a rectangular plot of land for a school in his village. When he was asked to give dimensions of the plot, he told that if its length is decreased by 50 m and breadth is increased by 50m, then its area will remain same, but if length is decreased by 10m & breadth is decreased by 20m, then area will decrease by 5300 m2 Based on the information given above, answer the following questions: Question 1 The equations in terms of X and Y are (a) x – y = 50, 2x – y = 550 (b) x – y = 50, 2x + y = 550 (c) x + y = 50, 2x + y = 550 (d) x + y = 50, 2x + y = 550 Let Length of plot = x m Breadth of plot = y m Now, Area of plot = xy m2 Given that if its length is decreased by 50 m and breadth is increased by 50m, then its area will remain same (Length − 50) × (Breadth + 50) = Area (x − 50) × (y + 50) = xy x (y + 50) − 50 (y + 50) = xy xy + 50x − 50y − 2500 = xy 50x − 50y − 2500 = 0 50x − 50y = 2500 Dividing both sides by 50 x − y = 50 Also, if length is decreased by 10m & breadth is decreased by 20m, then area will decrease by 5300 m2 (Length − 10) × (Breadth − 20) = Area − 5300 (x − 10) × (y − 20) = xy − 5300 x (y − 20) − 10 (y − 20) = xy − 5300 xy − 20x − 10y + 200 = xy − 5300 −20x − 10y + 200 = −5300 −20x − 10y = −5300 − 200 −20x − 10y = −5500 20x + 10y = 5500 Dividing both sides by 10 2x + y = 550 Thus, our equations are x – y = 50, 2x + y = 550 So, the correct answer is (b) Question 2 Which of the following matrix equation is represented by the given information (a) [■8(1&−1@2&1)] [■8(𝑥@𝑦)] = [■8(50@550)] (b) [■8(1&1@2&1)] [■8(𝑥@𝑦)] = [■8(50@550)] (c) [■8(1&1@2&−1)] [■8(𝑥@𝑦)] = [■8(50@550)] (d) [■8(1&1@2&1)] [■8(𝑥@𝑦)] = [■8(−50@−550)] Since our equations are x – y = 50 2x + y = 550 Matrix equation will look like [■8(𝟏&−𝟏@𝟐&𝟏)] [■8(𝒙@𝒚)] = [■8(𝟓𝟎@𝟓𝟓𝟎)] So, the correct answer is (a) Question 3 The value of x (length of rectangular field) is (a) 150 m (b) 400 m (c) 200 m (d) 320 m Since our equations are x – y = 50 …(1) 2x + y = 550 …(1) Adding (1) and (2) (x – y) + (2x + y) = 50 + 550 3x = 600 x = 600/2 x = 200 m So, the correct answer is (c) Question 4 The value of y (breadth of rectangular field) is (a) 150m (b) 200m (c) 430m (d) 350m Putting x = 200 in (1) x − y = 50 200 − y = 50 200 − 50 = y 150 = y y = 150 m So, the correct answer is (a) Question 5 How much is the area of rectangular field? (a) 60000 sq. m. (b) 30000 sq. m. (c) 30000 m (d) 3000 m Area of rectangular field = Length × Breadth = 200 × 150 = 30,000 m2 = 30,000 sq. m So, the correct answer is (b)

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.