
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Last updated at Aug. 18, 2021 by Teachoo
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 4.3,1 Find area of the triangle with vertices at the point given in each of the following: (ii) (2, 7), (1, 1), (10, 8) The area of triangle is given by ∆ = 12 x1y11x2y21x3y31 Here, x1 = 2 , y1 = 7 x2 = 1 , y2 = 1 x3 = 10 , y3 = 8 ∆ = 12 2711111081 = 12 2 1181−7 11101+1 11108 = 12 ( 2(1 – 8) – 7(1 – 10) + 1 (8 – 10) ) = 12 (2( – 7) – 7( – 9) + 1 (– 2) ) = 12 ( – 14 + 63 – 2 ) = 12 [– 16 + 63] = 472 Thus, the required area of triangle is 𝟒𝟕𝟐 square units