
Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 4.5
Ex 4.5, 2
Ex 4.5, 3 Important
Ex 4.5, 4 Important
Ex 4.5, 5 You are here
Ex 4.5, 6 Important
Ex 4.5, 7
Ex 4.5, 8
Ex 4.5, 9
Ex 4.5, 10 Important
Ex 4.5, 11 Important
Ex 4.5, 12
Ex 4.5, 13
Ex 4.5, 14 Important
Ex 4.5, 15 Important
Ex 4.5, 16
Ex 4.5, 17 (MCQ) Important
Ex 4.5, 18 (MCQ) Important
Last updated at March 30, 2023 by Teachoo
Ex 4.5, 5 Find the inverse of each of the matrices (if it exists) [■8(2&−[email protected]&3)] Let A = [■8(2&−[email protected]&3)] We know that A-1 = 1/(|A|) adj A exists when |A|≠ 0 |A| = |■8(2&[email protected]&3)| = 2 × 3 – 4 × ( – 2) = 6 + 8 = 14 Since |A|≠ 0, A–1 exists Calculating adj A A =[■8(2&−[email protected]&3)] adj(A) = [■8(2&−[email protected]&3)] = [■8(3&[email protected]−4&2)] Calculating A–1 A-1 = 1/(|A|) adj A = 𝟏/𝟏𝟒 [■8(𝟑&𝟐@−𝟒&𝟐)]