Ex 4.5, 5 - Class 12
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 4.5, 5 Find the inverse of each of the matrices (if it exists) 2−243 Let A = 2−243 We know that A-1 = 1|A| adj A exists when |A|≠ 0 |A| = 2243 = 2 × 3 – 4 × ( – 2) = 6 + 8 = 14 Since |A|≠ 0, A–1 exists Calculating adj A A = 2−243 adj(A) = 2−243 = 32−42 Calculating A–1 A-1 = 1|A| adj A = 𝟏𝟏𝟒 𝟑𝟐−𝟒𝟐
Chapter 4 Class 12 Determinants
Serial order wise
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