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Ex 4.5, 6 - Class 12
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 4.5, 6 Find the inverse of each of the matrices (if it exists) 1532 Let A = 1532 We know that A-1 = 1|A| adj A exists when |A|≠ 0 |A| = 1532 = 1 × 2 − 3 × 5 = 2 − 15 = −13 Since |A|≠ 0, A–1 exists Calculating adj A A = 1532 adj(A) = 1532 = 2−5−31 Calculating A–1 A-1 = 1|A| adj A = 1−13 2−5−31 = 𝟏𝟏𝟑 −𝟐𝟓𝟑−𝟏
Chapter 4 Class 12 Determinants
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.