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Ex 3.2, 15 - Chapter 3 Class 12 Matrices (Term 1)
Last updated at March 30, 2023 by Teachoo
Ex 3.2
Ex 3.2, 1
Ex 3.2, 2 (i)
Ex 3.2, 2 (ii) Important
Ex 3.2, 2 (iii)
Ex 3.2, 2 (iv)
Ex 3.2, 3 (i)
Ex 3.2, 3 (ii) Important
Ex 3.2, 3 (iii)
Ex 3.2, 3 (iv) Important
Ex 3.2, 3 (v)
Ex 3.2, 3 (vi) Important
Ex 3.2, 4
Ex 3.2, 5
Ex 3.2, 6
Ex 3.2, 7 (i)
Ex 3.2, 7 (ii) Important
Ex 3.2, 8
Ex 3.2, 9
Ex 3.2, 10
Ex 3.2, 11
Ex 3.2, 12 Important
Ex 3.2, 13 Important
Ex 3.2, 14
Ex 3.2, 15 You are here
Ex 3.2, 16 Important
Ex 3.2, 17 Important
Ex 3.2, 18
Ex 3.2, 19 Important
Ex 3.2, 20 Important
Ex 3.2, 21 (MCQ) Important
Ex 3.2, 22 (MCQ) Important
Chapter 3 Class 12 Matrices
Serial order wise
Transcript
Ex 3.2, 15 Find A2 5A + 6I if A = [ 8(2&0&[email protected]&1&[email protected]& 1&0)] Finding A2 A2 = AA = [ 8(2&0&[email protected]&1&[email protected]& 1&0)] [ 8(2&0&[email protected]&1&[email protected]& 1&0)] = [ 8(2(2)+0(2)+1(1)&2(0)+0(1)+1( 1)&2(1)+0(3)+1(0)@2(2)+1(2)+3(1)&2(0)+1(1)+3( 1)&2(1)+1(3)+3(0)@1(2)+ 1(2)+0(1)&1(0)+ 1(1)+0( 1)&1(1)+ 1(3)+0(0))] = [ 8(4+0+1&0+0 1&[email protected]+2+3&0+1 3&[email protected] 2+0&0 1+0&1 3+0)] = [ 8(5& 1&[email protected]& 2&[email protected]& 1& 2)] Now calculating A2 5A + 6I = [ 8(5& 1&[email protected]& 2&[email protected]& 1& 2)] 5 [ 8(2&0&[email protected]&1&[email protected]& 1&0)]+ 6 [ 8(1&0&[email protected]&1&[email protected]&0&1)] = [ 8(5& 1&[email protected]& 2&[email protected]& 1& 2)] [ 8(2 5&0 5&1 [email protected] 5&1 5&3 [email protected] 5& 1 5&0 5)] + [ 8(1 6&0 6&0 [email protected] 6&1 6&0 [email protected] 6&0 6&1 6)] = [ 8(5& 1&[email protected]& 2&[email protected]& 1& 2)] - [ 8(10&0&[email protected]&5&[email protected]& 5&0)] + [ 8(6&0&[email protected]&6&[email protected]&0&6)] = [ 8(5 10+6& 1 0+0&2 [email protected] 10+0& 2 5+6&5 [email protected] 5+0& 1+5+0& 2 0+6)] = [ 8(1& 1& [email protected] 1& 1& [email protected] 5&4&4)]
