




Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 3.2
Ex 3.2, 2 (i)
Ex 3.2, 2 (ii) Important
Ex 3.2, 2 (iii)
Ex 3.2, 2 (iv)
Ex 3.2, 3 (i)
Ex 3.2, 3 (ii) Important
Ex 3.2, 3 (iii)
Ex 3.2, 3 (iv) Important
Ex 3.2, 3 (v)
Ex 3.2, 3 (vi) Important
Ex 3.2, 4
Ex 3.2, 5
Ex 3.2, 6
Ex 3.2, 7 (i)
Ex 3.2, 7 (ii) Important
Ex 3.2, 8
Ex 3.2, 9
Ex 3.2, 10
Ex 3.2, 11
Ex 3.2, 12 Important
Ex 3.2, 13 Important
Ex 3.2, 14
Ex 3.2, 15
Ex 3.2, 16 Important
Ex 3.2, 17 Important
Ex 3.2, 18
Ex 3.2, 19 Important
Ex 3.2, 20 Important
Ex 3.2, 21 (MCQ) Important
Ex 3.2, 22 (MCQ) Important
Last updated at Dec. 7, 2021 by Teachoo
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 3.2, 1 Let A = [■8(2&[email protected]&2)], B = [■8(1&[email protected]−2&5)], C = [■8(−2&[email protected]&4)] Find each of the following (i) A + B A + B = [■8(2&[email protected]&2)] + [■8( 1&[email protected]−2&5)] = [■8(2+1&[email protected]−2&2+5)] = [■8(𝟑&𝟕@𝟏&𝟕)] Ex 3.2,1 Let A = [■8(2&[email protected]&2)], B = [■8(1&[email protected]−2&5)], C = [■8(−2&[email protected]&4)] Find each of the following (ii) A – B A – B = [■8(2&[email protected]&2)]− [■8( 1&[email protected]−2&5)] = [■8(2−1&4−[email protected]−(−2)&2−5)] = [■8(1&[email protected]+2&−3)] = [■8(𝟏&𝟏@𝟓&−𝟑)] Ex 3.2, 1 Let A = [■8(2&[email protected]&2)], B = [■8(1&[email protected]−2&5)], C = [■8(−2&[email protected]&4)] Find each of the following 3A – C Finding 3A 3A = 3[■8(2&[email protected]&2)] = [■8(3 × 2&3 × [email protected] × 3 &3 × 2)] = [■8(𝟔&𝟏𝟐@𝟗&𝟔)] Hence 3A – C = [■8(6&[email protected]&6)] ⤶7− [■8(−2&[email protected]&4)] = [■8(6−(−2)&12−[email protected]−3&6−4)] = [■8(6+2&[email protected]&2)] = [■8(𝟖&𝟕@𝟔&𝟐)] Ex 3.2, 1 Let A = [■8(2&[email protected]&2)] B = [■8(1&[email protected]−2&5)] , C = [■8(−2&[email protected]&4)]. Find each of the following (iv)AB AB = [■8(2&[email protected]&2)] [■8(1&[email protected]−2&5)] = [■8(2 × 1+4 × −2 &2 × 3+4 × [email protected] × 1+2 × −2&3 × 3+2 × 5)] = [■8(2−8&[email protected]−4&9+10)] = [■8(−𝟔&𝟐𝟔@−𝟏&𝟏𝟗)] Ex 3.2, 1 Let A = [■8(2&[email protected]&2)] B = [■8(1&[email protected]−2&5)] , C = [■8(−2&[email protected]&4)]. Find each of the following (v) BA BA = [■8(1&[email protected]−2&5)] [■8(2&[email protected]&2)] = [■8(1 × 2+3 × 3 &1 × 4+3 × [email protected]−2 × 2+5 × 3&−2 × 4+5 × 2)] = [■8(2+9&[email protected]−4+15&−8+10)] = [■8(𝟏𝟏&𝟏𝟎@𝟏𝟏&𝟐)]