Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 3.2, 7 (i) - Chapter 3 Class 12 Matrices (Term 1)
Last updated at March 16, 2023 by Teachoo
Ex 3.2
Ex 3.2, 1
Ex 3.2, 2 (i)
Ex 3.2, 2 (ii) Important
Ex 3.2, 2 (iii)
Ex 3.2, 2 (iv)
Ex 3.2, 3 (i)
Ex 3.2, 3 (ii) Important
Ex 3.2, 3 (iii)
Ex 3.2, 3 (iv) Important
Ex 3.2, 3 (v)
Ex 3.2, 3 (vi) Important
Ex 3.2, 4
Ex 3.2, 5
Ex 3.2, 6
Ex 3.2, 7 (i) You are here
Ex 3.2, 7 (ii) Important
Ex 3.2, 8
Ex 3.2, 9
Ex 3.2, 10
Ex 3.2, 11
Ex 3.2, 12 Important
Ex 3.2, 13 Important
Ex 3.2, 14
Ex 3.2, 15
Ex 3.2, 16 Important
Ex 3.2, 17 Important
Ex 3.2, 18
Ex 3.2, 19 Important
Ex 3.2, 20 Important
Ex 3.2, 21 (MCQ) Important
Ex 3.2, 22 (MCQ) Important
Chapter 3 Class 12 Matrices
Serial order wise
Transcript
Ex 3.2, 7 Find X and Y, if (i) X + Y = [■8(7&[email protected]&5)] and X – Y = [■8(3&[email protected]&3)] Let X + Y = [■8(7&[email protected]&5)] X – Y = [■8(3&[email protected]&3)] Adding (1) and (2) X + Y + X – Y = [■8(7&[email protected]&5)] + [■8(3&[email protected]&3)] X + Y + X – Y = [■8(7+3&[email protected]+0&5+3)] 2X + 0 = [■8(10&[email protected]&8)] …(1) …(2) 2X = [■8(10&[email protected]&8)] X = 1/2 [■8(10&[email protected]&8)] X = [■8(10/2&0/[email protected]/2&8/2)] X = [■8(5&[email protected]&4)] Thus, X = [■8(5&[email protected]&4)] Putting value of X in (1) X + Y = [■8(7&[email protected]&5)] Y = [■8(7&[email protected]&5)] – X Y = [■8(7&[email protected]&5)] – [■8(5&[email protected]&4)] Y = [■8(7−5&0−[email protected]−1&5−4)] Y = [■8(2&[email protected]&1)] Hence, X = [■8(𝟓&𝟎@𝟏&𝟒)] & Y = [■8(𝟐&𝟎@𝟏&𝟏)]
