Ex 3.2, 10 - Chapter 3 Class 12 Matrices

Last updated at Dec. 16, 2024 by

ย  Ex 3.2, 10 - Solve for x, y, z, t, if 2 [x z y t] + 3 [1 -1 0 2] - Ex 3.2

part 2 - Ex 3.2, 10 - Ex 3.2 - Serial order wise - Chapter 3 Class 12 Matrices
part 3 - Ex 3.2, 10 - Ex 3.2 - Serial order wise - Chapter 3 Class 12 Matrices

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Ex 3.2,10 Solve the equation for x, y, z and t, if 2[โ– 8(๐‘ฅ&๐‘ง@๐‘ฆ&๐‘ก)] + 3 [โ– 8(1&โˆ’1@0&2)] = 3 [โ– 8(3&5@4&6)] 2[โ– 8(๐‘ฅ&๐‘ง@๐‘ฆ&๐‘ก)] + 3 [โ– 8(1&โˆ’1@0&2)] = 3 [โ– 8(3&5@4&6)] [โ– 8(๐‘ฅร—2&๐‘งร—2@๐‘ฆร—2&๐‘กร—2)] + [โ– 8(1ร—3&โˆ’1ร—3@0ร—3&2ร—3)] = [โ– 8(3ร—3&5ร—3@4ร—3&6ร—3)] [โ– 8(2๐‘ฅ&2๐‘ง@2๐‘ฆ&2๐‘ก)] + [โ– 8(3&โˆ’3@0&6)] = [โ– 8(9&15@12&18)] [โ– 8(2๐‘ฅ+3&2๐‘งโˆ’3@2๐‘ฆ+0&2๐‘ก+6)] = [โ– 8(9&15@12&18)] [โ– 8(๐Ÿ๐’™+๐Ÿ‘&๐Ÿ๐’›โˆ’๐Ÿ‘@๐Ÿ๐’š&๐Ÿ๐’•+๐Ÿ”)] = [โ– 8(๐Ÿ—&๐Ÿ๐Ÿ“@๐Ÿ๐Ÿ&๐Ÿ๐Ÿ–)] Since matrices are equal. Corresponding elements are equal 2x + 3 = 9 2y = 12 2z โ€“ 3 = 15 2t + 6 = 18 Solving equation (1) 2x + 3 = 9 2x = 9 โ€“ 3 x = 6/2 x = 3 Solving equation (2) 2y = 12 y = 12/2 y = 6 Solving equation (3) 2z โ€“ 3 = 15 2z = 15 + 3 z = 18/2 z = 9 Solving equation (4) 2t + 6 = 18 2t = 18 โ€“ 6 t = 12/2 t = 6 Hence x = 3 , y = 6 , z = 9 & t = 6

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo