Ex 3.2, 5 - Chapter 3 Class 12 Matrices
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 3.2, 5 If A = [ 8(2/3&1&5/3@1/3&2/3&4/3@7/3&2&2/3)] and B = [ 8(2/5&3/5&1@1/5&2/5&4/5@7/5&6/5&2/5)] ,then compute 3A 5B 3A 5B = 3 [ 8(2/3&1&5/3@1/3&2/3&4/3@7/3&2&2/3)] - 5 [ 8(2/5&3/5&1@1/5&2/5&4/5@7/5&6/5&2/5)] = [ 8(2/3 3&1 3&5/3 3@1/3 3&2/3 3&4/3 3@7/3 3&2 3&2/3 3)] [ 8(2/5 5&3/5 5&1 5@1/5 5&2/5 5&4/5 5@7/5 5&6/5 5&2/5 5 )] = [ 8(2&3&5@1&2&4@7&6&2)] [ 8(2&3&5@1&2&4@7&6&2)] = [ 8(2 2&3 3&5 5@1 1&2 2&4 4@7 7&6 6&2 2)] = [ 8(0&0&0@0&0&0@0&0&0)] Hence, 3A 5B = [ 8(0&0&0@0&0&0@0&0&0)]
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