Ex 3.2
Last updated at April 16, 2024 by Teachoo
Ex 3.2, 3 Compute the indicated products (vi) [■8(3&−1&3@−1&0&2)][■8(2&−3@1&0@3&1)] [■8(𝟑&−𝟏&𝟑@−𝟏&𝟎&𝟐)]_"2 × 3" [■8(𝟐&−𝟑@𝟏&𝟎@𝟑&𝟏)]_"3 × 2" = [■8(3(2)−1(1)+3(3)&3(−3)−1(0)+3(1)@−1(2)+0(1)+2(3)&−1(−3)+0(0)+2(1))]_(2 ×2) = [■8(6−1+9&−9−0+3@−2+0+6&3+0+2)] = [■8(𝟏𝟒&−𝟔@𝟒&𝟓)]