Last updated at Jan. 17, 2020 by Teachoo

Transcript

Ex 3.2, 12 Given 3[■8(x&y@z&w)] = [■8(x&6@−1&2w)] + [■8(4&x+y@z+w&3)] find the values of x, y, z and w. 3[■8(x&y@z&w)] = [■8(x&6@−1&2w)] + [■8(4&x+y@z+w&3)] [■8(3x&3y@3z&3w)] = [■8(x+4&6+x+y@1−z+w&2w+3)] Since matrices are equal. Corresponding elements are equal 3x = x + 4 3y = 6 + x + y 3z = 1 – z + w 3w = 2w + 3 …(1) …(2) Solving equation (1) 3x = x + 4 3x – x = 4 2x = 4 x = 4/2 x = 2 Solving equation (2) 3y = 6 + x + y 3y – y = 6 + x 2y = 6 + x Putting x = 2 2y = 6 + 2 2y = 8 y = 8/2 y = 4 Solving equation (4) 3w = 2w + 3 3w – 2w = 3 w = 3 Solving equation (3) 3z = – 1 + z + w 3z – z = – 1 + w 2z = – 1 + w Putting w = 3 2z = – 1 + 3 2z = 2 z = 2/2 z = 1 Hence, x = 2, y = 4 , w = 3 & z = 1

Ex 3.2

Ex 3.2, 1

Ex 3.2, 2

Ex 3.2, 3

Ex 3.2, 4

Ex 3.2, 5

Ex 3.2, 6

Ex 3.2, 7 Important

Ex 3.2, 8

Ex 3.2, 9

Ex 3.2, 10

Ex 3.2, 11

Ex 3.2, 12 Important You are here

Ex 3.2, 13 Important

Ex 3.2, 14

Ex 3.2, 15

Ex 3.2, 16 Important

Ex 3.2, 17 Important

Ex 3.2, 18 Important

Ex 3.2, 19 Important

Ex 3.2, 20 Important

Ex 3.2, 21 Important

Ex 3.2, 22 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.