![[Class 9 Ganita Manjari] Find the perimeters of the following shapes - Exercise Set 6.1](https://cdn.teachoo.com/0e3518b6-b092-428d-abde-7b66dd648d25/slide89.jpg)
Ex 6.1, 5 (ix)
Last updated at May 29, 2026 by Teachoo
Exercise Set 6.1
Ex 6.1, 1
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Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
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Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
Transcript
Ex 6.1, 5 (ix) Find the perimeters of the following shapes (taking the arcs to be quarter or half or three-quarters of a circle, as appropriate) Here, we have 1 big semicircle with Diameter = 10 + 10 = 20 cm 2 small semicircle with Diameter = 10 cm Now, Perimeter of shape = Circumference of semicircle with Diameter 20 cm + 2 × Circumference of semicircle with Diameter 10 cm = Circumference of semicircle with Radius 10 cm + 2 × Circumference of semicircle with Radius 5 cm = 𝟏/𝟐 × 𝟐 × 𝝅 × 𝟏𝟎+𝟐 × (𝟏/𝟐 × 𝟐 × 𝝅 × 𝟓) = 𝜋 × 10+2 × 𝜋 × 5 = 𝜋 × 10+ 𝜋 × 10 = 𝜋 × (10+10) = 𝝅 × 𝟐𝟎 = 22/7 × 20 = 440/7 = 62.85 cm
