Ex 6.1, 5 (vi)
Last updated at May 29, 2026 by Teachoo
None
Exercise Set 6.1
Ex 6.1, 1
You are here
You are here
Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
-
Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
Transcript
Ex 6.1, 5 (vi) Find the perimeters of the following shapes (taking the arcs to be quarter or half or three-quarters of a circle, as appropriate) Here, 28 cm is divided into 4 equal parts ∴ Length of each part = 28/4 = 7 cm Let’s label our figure and find perimeter Now, Perimeter of figure = Circumference of Big Semicircle with Diameter 28 cm + 4 × Circumference of Semi circle with Diameter 7 cm = Circumference of Big Semicircle with Radius 14 cm + 4 × Circumference of Semi circle with radius 7/2 cm = 𝟏/𝟐 × 𝟐 × 𝝅 × 𝟏𝟒 +"4 × " (𝟏/𝟐 × 𝟐 × 𝝅 ×𝟕/𝟐) = 𝜋 × 14+"2 ×" 𝜋 × 7 = 14𝜋+14𝜋 = 𝟐𝟖𝝅 = 28 ×22/7 = 4 × 22 = 88 cm
