Ex 6.1, 5 (ii)
Last updated at May 29, 2026 by Teachoo
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Exercise Set 6.1
Ex 6.1, 1
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Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
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Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmaguptaβs Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
Transcript
Ex 6.1, 5 (ii) Find the perimeters of the following shapes (taking the arcs to be quarter or half or three-quarters of a circle, as appropriate) Letβs label all sides and radius Here, there are two straight edges And, Length of one straight edge = (ππ β π)/π = 4/2 = 2 cm Now, Perimeter of shape = Perimeter of semicircle with Diameter 12 cm + Perimeter of semicircle with Diameter 8 cm + Length of two straight edges = Perimeter of semicircle with Radius 6 cm + Perimeter of semicircle with radius 4 cm + 2 Γ Length of one straight edge = 1/2 Γ 2π Γ 6+1/2 Γ 2π Γ 4+2 Γ 2 = π Γ π+π Γ π+π Γ π = π Γ (6+4)+4 = πππ +π = 10 Γ22/7+4 = 220/7+4 = (220 + 4 Γ 7)/7 = (220 + 28)/7 = 248/7 = 35.42 cm
