Ex 6.1, 5 (viii)
Last updated at May 29, 2026 by Teachoo
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Exercise Set 6.1
Ex 6.1, 1
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Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
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Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
Transcript
Ex 6.1, 5 (viii) Find the perimeters of the following shapes (taking the arcs to be quarter or half or three-quarters of a circle, as appropriate) Here, we have 1 big semicircle with Diameter = 4 + 4 + 4 = 12 cm 3 small semicircle with Diameter = 4 cm Now, Perimeter of shape = Circumference of semicircle with Diameter 12 cm + 3 × Circumference of semicircle with Diameter 4 cm = Circumference of semicircle with Radius 6 cm + 3 × Circumference of semicircle with Radius 2 cm = 𝟏/𝟐 × 𝟐 × 𝝅 × 𝟔+𝟑 × (𝟏/𝟐 × 𝟐 × 𝝅 × 𝟐) = 𝜋 × 6+3 × 𝜋 × 2 = 𝜋 × 6+ 𝜋 × 6 = 𝜋 × (6+6) = 𝝅 × 𝟏𝟐 = 22/7 × 12 = 264/7 = 37.71 cm
