Ex 6.1, 5 (iv)
Last updated at May 29, 2026 by Teachoo
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Exercise Set 6.1
Ex 6.1, 1
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Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
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Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmagupta’s Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
Transcript
Ex 6.1, 5 (iv) Find the perimeters of the following shapes (taking the arcs to be quarter or half or three-quarters of a circle, as appropriate) Here, we have an equilateral triangle of side 12 cm On each side, there is a semicircle of Diameter = Side = 12 cm Now, Perimeter of shape = 3 × Perimeter of Semicircle of Diameter 12 cm = 3 × Perimeter of Semicircle of Radius 6 cm = 3 × 1/2 × 2𝜋r = 3 × 𝜋r = 3 × 22/7 × 6 = 396/7 = 56.57 cm
