Find : ∫√(x/(1-x^3 )) dx; x∈(0,1)
This question is similar to Misc 12 Chapter 7 Class 12

CBSE Class 12 Sample Paper for 2024 Boards
CBSE Class 12 Sample Paper for 2024 Boards
Last updated at Feb. 10, 2025 by Teachoo
Transcript
โซโ(๐ฅ/(1 โ ๐ฅ^3 )) ๐๐ฅ = โซ1โโ๐ฅ/โ(1 โ ๐ฅ^3 ) ๐๐ฅ Let ๐=๐^(๐/๐) Differentiating w.r.t. ๐ฅ ๐๐ก/๐๐ฅ=3/2 ๐ฅ^(3/2 โ1) ๐๐ก/๐๐ฅ=3/2 ๐ฅ^(1/2 ) ๐๐ก/๐๐ฅ=3/2 โ๐ฅ ๐/๐ ๐๐ญ=โ๐ ๐ ๐ Now, our equation becomes โซ1โโ๐ฅ/โ(1 โ ๐ฅ^3 ) ๐๐ฅ=โซ1โใ2/(3โ(1 โใ ๐ฅใ^3 )) ๐๐กใ = ๐/๐ โซ1โ๐ ๐/โ(๐ โ ๐^๐ )dt = 2/3 sin^(โ1)โกใ๐ก+๐ใ Putting back ๐ก=๐ฅ^(3/2) = ๐/๐ ใ๐๐๐ใ^(โ๐)โกใใ(๐ใ^(๐/๐))+๐ใ