Find the domain of sin^(-1) (x^2-4)

This question is similar to Question-19 CBSE Class-12 Sample Paper for 2023 Boards

Find the domain of sin^-1 (x^2 - 4) - Teachoo Class 12 (with Video) - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 21 (Choice 2) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

 

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Transcript

We know that Domain of 〖𝑠𝑖𝑛〗^(−1) 𝜃 𝑖𝑠 "[–1, 1]" Thus, we can write −1≤𝜃≤1 Putting θ = 𝑥^2−4 −𝟏 ≤𝒙^𝟐−𝟒≤𝟏" " Adding 4 on both sides 1+4 ≤𝑥^2−4+4≤1" "+ 4 𝟑 ≤𝒙^𝟐≤"5" Taking square root both sides ±√𝟑 ≤𝒙≤±√𝟓 " " So, we can write −√𝟓<𝒙 ≤−√𝟑 and √𝟑<𝒙 ≤√𝟓 Thus, Domain of〖 sin〗^(−1) (𝑥^2−4)𝑖𝑠 [−√𝟓, −√(𝟑 )]∪[√(𝟑 ), √𝟓] " "

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