sin [π/3-sin (-1)⁡ (-1/2) ] is equal to :

(a) 1/2  (b) 1/3

(c) −1  (d) 1

 

This question is inspired from Ex 2.2, 20 (MCQ) - Chapter 2 Class 12 - Inverse Trigonometric Functions

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Transcript

Question 1 sin [𝜋/3−sin^(−1)⁡(−1/2) ] is equal to : (a) 1/2 (b) 1/3 (c) −1 (d) 1 sin⁡[𝜋/3− 〖𝐬𝐢𝐧〗^(−𝟏)⁡(−𝟏/𝟐) ] = sin⁡[𝜋/3−(− 〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) )] = sin⁡[𝜋/3+〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) ] = sin⁡[𝜋/3+𝜋/𝟔] = sin⁡〖𝜋/2〗 = 1 So, the correct answer is (d)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.