sin [π/3-sin (-1)⁡ (-1/2) ] is equal to :

(a) 1/2  (b) 1/3

(c) −1  (d) 1

 

This question is inspired from Ex 2.2, 20 (MCQ) - Chapter 2 Class 12 - Inverse Trigonometric Functions

Slide1.JPG

Advertisement

Slide2.JPG

Advertisement

  1. Class 12
  2. Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Transcript

Question 1 sin [𝜋/3−sin^(−1)⁡(−1/2) ] is equal to : (a) 1/2 (b) 1/3 (c) −1 (d) 1 sin⁡[𝜋/3− 〖𝐬𝐢𝐧〗^(−𝟏)⁡(−𝟏/𝟐) ] = sin⁡[𝜋/3−(− 〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) )] = sin⁡[𝜋/3+〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) ] = sin⁡[𝜋/3+𝜋/𝟔] = sin⁡〖𝜋/2〗 = 1 So, the correct answer is (d)

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.