sin [π/3-sin (-1)⁡ (-1/2) ] is equal to :

(a) 1/2  (b) 1/3

(c) −1  (d) 1

 

This question is inspired from Ex 2.2, 20 (MCQ) - Chapter 2 Class 12 - Inverse Trigonometric Functions

Slide1.JPG

Slide2.JPG

Something went wrong!

The video couldn't load due to a technical hiccup.
But don't worry — our team is already on it, and we're working hard to get it back up ASAP.

Thanks for bearing with us!

Share on WhatsApp

Transcript

Question 1 sin [𝜋/3−sin^(−1)⁡(−1/2) ] is equal to : (a) 1/2 (b) 1/3 (c) −1 (d) 1 sin⁡[𝜋/3− 〖𝐬𝐢𝐧〗^(−𝟏)⁡(−𝟏/𝟐) ] = sin⁡[𝜋/3−(− 〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) )] = sin⁡[𝜋/3+〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝟏/𝟐) ] = sin⁡[𝜋/3+𝜋/𝟔] = sin⁡〖𝜋/2〗 = 1 So, the correct answer is (d)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo