If A = [aij] is a square matrix of order 2 such that aij = {(1,Β when i β j 0,Β when i=jΒ )β€ , then A2 is :
(a) [8(1 0 1 0)]Β (b) [8(1 1 0 0)]Β Β Β (c) [8(1 1 1 0)]Β (d) [8(1 0 0 1)]Β
Last updated at Sept. 4, 2021 by
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Question 3 If A = [πππ] is a square matrix of order 2 such that πππ = {β(1, π€βππ π β π@0, π€βππ π=π )β€ , then A2 is : (a) [β 8(1&0@1&0)] (b) [β 8(1&1@0&0)] (c) [β 8(1&1@1&0)] (d) [β 8(1&0@0&1)] For a 2 Γ 2 matrix A = [β 8(π_11&π_12@π_21&π_22 )] Given that π_ππ={β(1, πβ π@0, π=π)β€ Thus, π_11 = 0, π_22 = 0 , π_12 = 1, π_21 = 1 So, our matrix becomes A = [β 8(π&π@π&π)] Now, A2 = [β 8(0&1@1&0)][β 8(0&1@1&0)] = [β 8(0(0)+1(1)&0(1)+1(0)@1(0)+0(1)&1(1)+0(0))] = [β 8(π&π@π&π)] So, the correct answer is (d)
CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
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CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
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