CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)

Class 12
Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

## (c) β6, 4, 9Β  Β  Β  Β  Β  Β  Β  Β  Β  Β (d) β6, 12, 18

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Question 32 If A = [β 8(0&[email protected]&β4)] and kA = [β 8(0&3π@2π&24)], then the values of π,π and π respectively are: (a) β6, β12, β18 (b) β6, β4, β9 (c) β6, 4, 9 (d) β6, 12, 18 Now, A = [β 8(0&[email protected]&β4)] kA = k [β 8(0&[email protected]&β4)] kA = [β 8(0 Γ π&2 Γ π@3 Γ π&β4 Γ π)] kA = [β 8(0&2π@3π&β4π)] Putting value of kA [β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)] Thus, 24 = β4k β4k = 24 k = 24/(β4) k = β6 Also, 3a = 2k 3a = 2(β6) 3a = β12 a = (β12)/3 a = β4 So, the correct answer is (B) [β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)] Thus, 24 = β4k β4k = 24 k = 24/(β4) k = β6 Also, 3a = 2k 3a = 2(β6) 3a = β12 a = (β12)/3 a = β4 2b = 3k 2b = 3(β6) 2b = β18 b = (β18)/2 b = β9 Thus, k = β6, a = β4, b = β9 So, the correct answer is (B)

#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.