Question 32 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards
Last updated at March 22, 2023 by Teachoo
If A = [8(0 2 3 -4)] and kA = [8(0 3a 2b 24)], then the values of π,π and π respectively are:
Question 32 If A = [β 8(0&[email protected]&β4)] and kA = [β 8(0&3π@2π&24)], then the values of π,π and π respectively are: (a) β6, β12, β18 (b) β6, β4, β9 (c) β6, 4, 9 (d) β6, 12, 18
Now,
A = [β 8(0&[email protected]&β4)]
kA = k [β 8(0&[email protected]&β4)]
kA = [β 8(0 Γ π&2 Γ π@3 Γ π&β4 Γ π)]
kA = [β 8(0&2π@3π&β4π)]
Putting value of kA
[β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)]
Thus,
24 = β4k
β4k = 24
k = 24/(β4)
k = β6
Also,
3a = 2k
3a = 2(β6)
3a = β12
a = (β12)/3
a = β4
So, the correct answer is (B)
[β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)]
Thus,
24 = β4k
β4k = 24
k = 24/(β4)
k = β6
Also,
3a = 2k
3a = 2(β6)
3a = β12
a = (β12)/3
a = β4
2b = 3k
2b = 3(β6)
2b = β18
b = (β18)/2
b = β9
Thus,
k = β6, a = β4, b = β9
So, the correct answer is (B)
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
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