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Question 32 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at March 22, 2023 by

If A = [8(0 2 3 -4)] and kA = [8(0 3a 2b 24)], then the values of π‘˜,π‘Ž and 𝑏 respectively are:

(a) βˆ’6, βˆ’12, βˆ’18Β  Β  Β  Β  Β  (b) βˆ’6, βˆ’4, βˆ’9

(c) βˆ’6, 4, 9Β  Β  Β  Β  Β  Β  Β  Β  Β  Β (d) βˆ’6, 12, 18

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Transcript

Question 32 If A = [β– 8(0&[email protected]&βˆ’4)] and kA = [β– 8(0&3π‘Ž@2𝑏&24)], then the values of π‘˜,π‘Ž and 𝑏 respectively are: (a) βˆ’6, βˆ’12, βˆ’18 (b) βˆ’6, βˆ’4, βˆ’9 (c) βˆ’6, 4, 9 (d) βˆ’6, 12, 18 Now, A = [β– 8(0&[email protected]&βˆ’4)] kA = k [β– 8(0&[email protected]&βˆ’4)] kA = [β– 8(0 Γ— π‘˜&2 Γ— π‘˜@3 Γ— π‘˜&βˆ’4 Γ— π‘˜)] kA = [β– 8(0&2π‘˜@3π‘˜&βˆ’4π‘˜)] Putting value of kA [β– 8(0&3π‘Ž@2𝑏&24)] = [β– 8(0&2π‘˜@3π‘˜&βˆ’4π‘˜)] Thus, 24 = βˆ’4k βˆ’4k = 24 k = 24/(βˆ’4) k = βˆ’6 Also, 3a = 2k 3a = 2(βˆ’6) 3a = βˆ’12 a = (βˆ’12)/3 a = βˆ’4 So, the correct answer is (B) [β– 8(0&3π‘Ž@2𝑏&24)] = [β– 8(0&2π‘˜@3π‘˜&βˆ’4π‘˜)] Thus, 24 = βˆ’4k βˆ’4k = 24 k = 24/(βˆ’4) k = βˆ’6 Also, 3a = 2k 3a = 2(βˆ’6) 3a = βˆ’12 a = (βˆ’12)/3 a = βˆ’4 2b = 3k 2b = 3(βˆ’6) 2b = βˆ’18 b = (βˆ’18)/2 b = βˆ’9 Thus, k = βˆ’6, a = βˆ’4, b = βˆ’9 So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.