Question 32 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards
Last updated at Sept. 4, 2021 by Teachoo
If A = [8(0 2 3 -4)] and kA = [8(0 3a 2b 24)], then the values of π,π and π respectively are:
Question 32 If A = [β 8(0&2@3&β4)] and kA = [β 8(0&3π@2π&24)], then the values of π,π and π respectively are: (a) β6, β12, β18 (b) β6, β4, β9 (c) β6, 4, 9 (d) β6, 12, 18
Now,
A = [β 8(0&2@3&β4)]
kA = k [β 8(0&2@3&β4)]
kA = [β 8(0 Γ π&2 Γ π@3 Γ π&β4 Γ π)]
kA = [β 8(0&2π@3π&β4π)]
Putting value of kA
[β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)]
Thus,
24 = β4k
β4k = 24
k = 24/(β4)
k = β6
Also,
3a = 2k
3a = 2(β6)
3a = β12
a = (β12)/3
a = β4
So, the correct answer is (B)
[β 8(0&3π@2π&24)] = [β 8(0&2π@3π&β4π)]
Thus,
24 = β4k
β4k = 24
k = 24/(β4)
k = β6
Also,
3a = 2k
3a = 2(β6)
3a = β12
a = (β12)/3
a = β4
2b = 3k
2b = 3(β6)
2b = β18
b = (β18)/2
b = β9
Thus,
k = β6, a = β4, b = β9
So, the correct answer is (B)
Made by
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.
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