CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)

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Question 2 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at May 29, 2023 by

The value of k (k < 0) for which the function f defined as
f (x)={((1 -cos⁡kx)/(x sin⁡x ),x≠0  1/2,x=0)┤ is continuous at x = 0 is :

(a) ±  1  (b) −1      (c) ±  1/2  (d) 1/2

This question is inspired from -   Question 21 - CBSE Class 12 Sample Paper for 2021 Boards

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Question 2 The value of k (k < 0) for which the function f defined as 𝑓 (π‘₯)={β–ˆ((1 βˆ’cosβ‘π‘˜π‘₯)/(π‘₯ sin⁑π‘₯ ),π‘₯β‰ 0@1/2, π‘₯=0)─ is continuous at x = 0 is : (a) Β± 1 (b) βˆ’1 (c) Β± 1/2 (d) 1/2 Given that function is continuous at x = 0 𝑓(π‘₯) is continuous at x = 0 i.e. (π₯𝐒𝐦)┬(π±β†’πŸŽ) 𝒇(𝒙)=𝒇(𝟎) Limit at x β†’ 0 (π‘™π‘–π‘š)┬(π‘₯β†’0) f(x) = (π‘™π‘–π‘š)┬(β„Žβ†’0) f(h) = lim┬(hβ†’0) (1 βˆ’ cosβ‘π‘˜β„Ž)/(β„Ž (sinβ‘β„Ž) ) = lim┬(hβ†’0) (𝟐 〖𝐬𝐒𝐧〗^πŸβ‘γ€–π’Œπ’‰/πŸγ€—)/(β„Ž (sinβ‘β„Ž)) = lim┬(hβ†’0) (2 sin^2β‘γ€–π‘˜β„Ž/2γ€—)/1 Γ—1/(β„Ž (sinβ‘β„Ž)) = (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) (𝟐 γ€–π’”π’Šπ’γ€—^πŸβ‘γ€–π’Œπ’‰/πŸγ€—)/(π’Œπ’‰/𝟐)^𝟐 Γ— (π’Œπ’‰/𝟐)^𝟐/(𝒉 (π’”π’Šπ’β‘π’‰)) = lim┬(hβ†’0) (2 sin^2β‘γ€–π‘˜β„Ž/2γ€—)/(π‘˜β„Ž/2)^2 Γ— (π‘˜^2 β„Ž^2)/(4β„Ž (sinβ‘β„Ž)) = lim┬(hβ†’0) sin^2β‘γ€–π‘˜β„Ž/2γ€—/(π‘˜β„Ž/2)^2 Γ— (π’Œ^𝟐 𝒉)/(𝟐(π’”π’Šπ’β‘π’‰)) = π’Œ^𝟐/𝟐 lim┬(hβ†’0) sin^2β‘γ€–π‘˜β„Ž/2γ€—/(π‘˜β„Ž/2)^2 Γ— β„Ž/sinβ‘β„Ž = π‘˜^2/2 lim┬(hβ†’0) sin^2β‘γ€–π‘˜β„Ž/2γ€—/(π‘˜β„Ž/2)^2 Γ—lim┬(hβ†’0) β„Ž/sinβ‘β„Ž = π‘˜^2/2 Γ— 1 Γ— 1 = π’Œ^𝟐/𝟐 Now, (π₯𝐒𝐦)┬(π±β†’πŸŽ) 𝒇(𝒙)=𝒇(𝟎) π‘˜^2/2 = 1/2 π‘˜^2 =1 π’Œ =±𝟏 But, given that k < 0 Thus, only value is k = βˆ’1 So, the correct answer is (b)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.