Find the value(s) of k so that the following function is continuous at π₯ = 0
f (x) = {
1- cos ⁡kx / x sin⁡x if x≠0
1/2 if x=0
CBSE Class 12 Sample Paper for 2021 Boards
CBSE Class 12 Sample Paper for 2021 Boards
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 21 Find the value(s) of k so that following function is continuous at π₯ = 0, f (x) = {β((1 β cosβ‘ππ₯)/(π₯ sinβ‘π₯ ) ππ π₯β 0@ 1/2 ππ π₯=0)β€ Given that function is continuous at x = 0 π(π₯) is continuous at x = 0 i.e. limβ¬(xβ0) π(π₯)=π(0) Limit at x β 0 (πππ)β¬(π₯β0) f(x) = (πππ)β¬(ββ0) f(h) = limβ¬(hβ0) (1 β cosβ‘πβ)/(β (sinβ‘β) ) = limβ¬(hβ0) (2 sin^2β‘γπβ/2γ)/(β (sinβ‘β)) = limβ¬(hβ0) (2 sin^2β‘γπβ/2γ)/1 Γ1/(β (sinβ‘β)) = limβ¬(hβ0) (2 sin^2β‘γπβ/2γ)/(πβ/2)^2 Γ (πβ/2)^2/(β (sinβ‘β)) = limβ¬(hβ0) (2 sin^2β‘γπβ/2γ)/(πβ/2)^2 Γ (π^2 β^2)/(4β (sinβ‘β)) = limβ¬(hβ0) (2 sin^2β‘γπβ/2γ)/(πβ/2)^2 Γ (π^2 β)/(4 (sinβ‘β)) = π^2/2 limβ¬(hβ0) sin^2β‘γπβ/2γ/(πβ/2)^2 Γ β/sinβ‘β = π^2/2 limβ¬(hβ0) sin^2β‘γπβ/2γ/(πβ/2)^2 Γlimβ¬(hβ0) β/sinβ‘β = π^2/2 Γ 1 Γ 1 = π^π/π Now, limβ¬(xβ0) π(π₯)=π(0) π^2/2 = 1/2 π^2 =1 π =Β±π Hence, k = 1, β1