Question 14 Find the coordinates of the point where the line (π₯ + 3)/3 = (π¦ β 1)/(β1) = (π§ β 5)/(β5) cuts the XY Plane.
If line (π₯ + 3)/3 = (π¦ β 1)/(β1) = (π§ β 5)/(β5) cuts the XY Plane
Then z = 0
So, let coordinates of point be (x, y, 0)
Now,
(π₯ + 3)/3 = (π¦ β 1)/(β1) = (π§ β 5)/(β5) = k
Thus,
x = 3k β 3, y = βk + 1, z = β5k + 5
Since z = 0
β5k + 5 = 0
5k = 5
k = 5/5
k = 1
Now,
x = 3k β 3 = 3(1) β 3 = 0
y = βk + 1 = β1 + 1 = 0
Thus, Coordinates of Point are (0, 0, 0)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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