Find ∫ ๐‘’ ๐‘ฅ (1 − cot ๐‘ฅ + ๐‘๐‘œ๐‘ ๐‘’๐‘ 2 ๐‘ฅ) ๐‘‘

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  1. Class 12
  2. Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Transcript

Question 7 (Choice 1) Find โˆซ ๐‘’๐‘ฅ (1 โˆ’ cot ๐‘ฅ + ๐‘๐‘œ๐‘ ๐‘’๐‘2๐‘ฅ) ๐‘‘x โˆซ ๐‘’๐‘ฅ ( [1 โˆ’ cot ๐‘ฅ] + ๐‘๐‘œ๐‘ ๐‘’๐‘2๐‘ฅ) ๐‘‘x It is of the form โˆซ1โ–’ใ€–๐’†^๐’™ [๐’‡(๐’™)+๐’‡^โ€ฒ (๐’™)] ใ€— ๐’…๐’™=๐’†^๐’™ ๐’‡(๐’™)+๐‘ช Where ๐‘“(๐‘ฅ)=1โˆ’cotโก๐‘ฅ ๐‘“^โ€ฒ (๐‘ฅ)=0โˆ’(โˆ’๐‘๐‘œ๐‘ ๐‘’๐‘^2 ๐‘ฅ)=๐‘๐‘œ๐‘ ๐‘’๐‘^2 ๐‘ฅ So, our equation becomes โˆซ ๐‘’๐‘ฅ ( [1 โˆ’ cot ๐‘ฅ] + ๐‘๐‘œ๐‘ ๐‘’๐‘2๐‘ฅ) ๐‘‘x" " = ๐’†^๐’™ (๐Ÿโˆ’๐’„๐’๐’• ๐’™) +๐‘ช

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.