Find the general solution of the following differential equation: š‘„ š‘‘š‘¦ āˆ’ (š‘¦ + 2š‘„ 2 )š‘‘š‘„ = 0

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Find general solution of differential equation: xdy - (y + 2x^2)dx = 0

Question 35 - CBSE Class 12 Sample Paper for 2021 Boards - Part 2
Question 35 - CBSE Class 12 Sample Paper for 2021 Boards - Part 3

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Question 35 Find the general solution of the following differential equation: š‘„ š‘‘š‘¦ āˆ’ (š‘¦ + 2š‘„2 )š‘‘š‘„ = 0 Given š‘„ š‘‘š‘¦ = (š‘¦ + 2š‘„2 )š‘‘š‘„ š‘‘š‘¦/š‘‘š‘„=(š‘¦ + 2š‘„^2)/š‘„ š‘‘š‘¦/š‘‘š‘„=š‘¦/š‘„+2š‘„ š’…š’š/š’…š’™āˆ’š’š/š’™=šŸš’™ Comparing with š’…š’š/š’…š’™ + Py = Q ∓ P = (āˆ’1)/š‘„ and Q = 2x Find integrating factor IF IF = e^∫1ā–’š‘ƒš‘‘š‘„ IF = š‘’^∫1▒〖(āˆ’1)/š‘„ š‘‘š‘„ć€— IF = š‘’^(āˆ’logā”š‘„ ) IF = š‘’^log⁔〖(š‘„)^(āˆ’1) 怗 IF = š‘’^怖log 〗⁔〖1/š‘„ć€— IF = šŸ/š’™ Solution of the equation y Ɨ I.F = ∫1ā–’ć€–š‘ø Ɨ š‘°.š‘­.š’…š’™+š’„ 怗 Putting values, š‘¦ Ɨ1/š‘„ = ∫1▒〖2š‘„ Ɨ1/š‘„ š‘‘š‘„ć€—+š¶ š‘¦/š‘„ = ∫1ā–’2š‘‘š‘„+š¶ š‘¦/š‘„ = 2š‘„+š¶ š’š = šŸš’™^šŸ+š‘Ŗš’™

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo