The value of |A|, if A=[0 2x-1 √x 1-2x 0 2√x -√x -2√x 0)], where x∈R^+, is
(a) (2x+1)^2 (b) 0 (c) (2x+1)^3 (d) (2x-1)^2

CBSE Class 12 Sample Paper for 2024 Boards
CBSE Class 12 Sample Paper for 2024 Boards
Last updated at Feb. 10, 2025 by Teachoo
Given π΄=[β (0&2π₯β1&βπ₯@1β2π₯&0&2βπ₯@ββπ₯&β2βπ₯&0)] Since diagonal elements are 0, this might be a skew symmetric matrix Letβs check Finding π¨^π» π΄^π=[β (0&1β2π₯&ββπ₯@2π₯β1&0&β2βπ₯@βπ₯&2βπ₯&0)] π΄^π=β[β (0&2π₯β1&βπ₯@1β2π₯&0&2βπ₯@ββπ₯&β2βπ₯&0)] π¨^π»= β A Since π΄^π= βA β΄ A is a skew symmetric matrix of order 3 We know that , Determinant of every skew symmetric matrix of odd order is 0. β΄ |A| = 0 So, the correct answer is (b)