CBSE Class 12 Sample Paper for 2024 Boards
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CBSE Class 12 Sample Paper for 2024 Boards
Last updated at August 14, 2026 by Teachoo
This question is similar to Question 9 Chapter 13 Class 12
![[Class 12 SQP] The random variable X has probability distribution P(X) - CBSE Class 12 Sample Paper for 2024 Boards](https://cdn.teachoo.com/a6fc7681-0516-4822-ae68-6b762123027e/slide10.jpg)
Transcript
(i) Find k Since X is a random variable , its Sum of Probabilities is equal to 1 P(X = 0) + P(X = 1) + P(X = 2) = 1 k + 2k + 3k = 1 6k = 1 k = 𝟏/𝟔 Our probability distribution table is P(X < 2) = P(X = 0) + P(X = 1) = k + 2k = 3k = 3 × 𝟏/𝟔 = 𝟏/𝟐 (iii) Find P (X > 2) Given 𝑃(𝑋)={■(𝑘," if " 𝑥=0@2𝑘," if " 𝑥=1@3𝑘," if " 𝑥=2@█(0," otherwise" @" " ))┤ For value of X other than 0, 1 and 2, the P(X) = 0 P(X > 2) = P(X = 3) + P(X = 4) + …… = 0 + 0 + ….. = 0
