The general solution of the differential equation π¦ππ₯ − π₯ππ¦ = 0 ; (Given x,y >0) is of the form
(a) π₯π¦ = πΆ (b) π₯ = γCyγ^2 (c) π¦ = πΆπ₯ (d) π¦ = Cx^2
(Where ‘c’ is an arbitrary positive constant of integration)
This question is exactly same as Question-15 CBSE Class 12 Sample Paper for 2023 Boards
Please check https://www.teachoo.com/19121/4115/Question-15/category/CBSE-Class-12-Sample-Paper-for-2023-Boards/
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