Question 15 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 14, 2026 by Teachoo

The general solution of the differential equation 𝑦𝑑𝑥 − 𝑥𝑑𝑦 = 0 ; (Given x,y >0) is of the form

(a) 𝑥𝑦 = 𝐶 (b) 𝑥 = 〖Cy〗^2 (c) 𝑦 = 𝐶𝑥 (d) 𝑦 = Cx^2

(Where ‘c’ is an arbitrary positive constant of integration)

This question is exactly same as Question-15 CBSE Class 12 Sample Paper for 2023 Boards

Please check https://www.teachoo.com/19121/4115/Question-15/category/CBSE-Class-12-Sample-Paper-for-2023-Boards/

[MCQ] The general solution of differential equation ydx - xdy = 0 is - CBSE Class 12 Sample Paper for 2024 Boards

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