In what direction is the ring getting pulled?
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CBSE Class 12 Sample Paper for 2024 Boards
CBSE Class 12 Sample Paper for 2024 Boards
Last updated at August 8, 2026 by Teachoo
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Transcript
To find direction, we need to find Resultant force Now, Resultant force exerted by teams (š ā) = š ā+š ā+š ā = āš Ė + š Ė This is in direction of š ā . Finding angle of vector š ā with respect to x-axis Now, Resultant force (š ā) = āš Ė + š Ė And, Vector of x-axis = š„ ā = š Ė Now, š¹ ā.š„ ā=|š¹ ā ||š„ ā | cosā”ćš ć (āš Ė + š Ė) . š Ė = āš Ć 1 Ć cos Īø ā1 = ā2 Ć cos Īø (ā1)/ā2 = cos Īø cos Īø = (āš)/āš Since cos is negative ā“ Angle is in second quadrant And, cos š /š = š/āš Therefore, Required angle = š ā š/4 = šš /š