The degree of the differential equation [1+(dy/dx)^2 ]^3=((d^2 y)/(dx^2 ))^2 is

(a) 4           (b) 3/2                   (c) 2              (d) Not defined

This question is similar to Question-2 CBSE-Class 12 Sample Paper for 2022-Boards For Term-2

[SQP] The degree of differential equation [1 + (dy/dx)^2]^3 = (y'')^2 - CBSE Class 12 Sample Paper for 2024 Boards

 

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Transcript

Given [1+(š‘‘š‘¦/š‘‘š‘„)^2 ]^3=((š‘‘^2 š‘¦)/(š‘‘š‘„^2 ))^2 [1+(š‘¦^′ )^2 ]^3=(š‘¦^′′ )^2 Since y’’ is the highest order of derivative Degree = Power of y’’ = 2 So, the correct answer is (c)

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