The corner points of the bounded feasible region determined by a system of linear constraints are (0,3),(1,1) and (3,0). Let Z = px + qy , where p,q>0. The condition on p and q so that the minimum of Z occurs at ( 3,0 ) and ( 1,1 ) is

(a) p=2qĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā  (b) p=q/2Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā  (c) p=3qĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā  (d) p=q

This question is similar to Question 38 Choice-2 CBSE Class 12 Sample Paper for 2021 Boards

[MCQ] The corner points of the bounded feasible region determined vt - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 7 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

The corner points given are (0, 3) ,(1, 1) and (3, 0) Since, minimum Z occurs at (3, 0) and (1,1) Thus Value of š‘=š‘š‘„+š‘žš‘¦ at (3, 0) = Value of š‘=š‘š‘„+š‘žš‘¦ at (1, 1) p(3) + q(0) = p(1) + q(1) 3p = p + q 3p āˆ’ p = q 2p = q p = š’’/šŸ So, the correct answer is (b)

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