The corner points of the bounded feasible region determined by a system of linear constraints are (0,3),(1,1) and (3,0). Let Z = px + qy , where p,q>0. The condition on p and q so that the minimum of Z occurs at ( 3,0 ) and ( 1,1 ) is

(a) p=2q              (b) p=q/2                   (c) p=3q                     (d) p=q

This question is similar to Question 38 Choice-2 CBSE Class 12 Sample Paper for 2021 Boards

[MCQ] The corner points of the bounded feasible region determined vt - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 7 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

 

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The corner points given are (0, 3) ,(1, 1) and (3, 0) Since, minimum Z occurs at (3, 0) and (1,1) Thus Value of 𝑍=𝑝𝑥+𝑞𝑦 at (3, 0) = Value of 𝑍=𝑝𝑥+𝑞𝑦 at (1, 1) p(3) + q(0) = p(1) + q(1) 3p = p + q 3p − p = q 2p = q p = 𝒒/𝟐 So, the correct answer is (b)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo