CBSE Class 12 Sample Paper for 2024 Boards

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Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 10, 2026 by

Find the value of γ€–sinγ€—^(-1) [cos(33π/5)]

This question is similar to Example-9 Chapter-2 Inverse trigonometry

[Class 12] Find the value of sin^-1 (cos (33π/5)) - Teachoo - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

 

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Transcript

sinβˆ’1 ("cos " 33Ο€/6) = sinβˆ’1 ("cos " (πŸ”π…+πŸ‘π…/πŸ“)) = sinβˆ’1 ("cos " 3πœ‹/5) = sinβˆ’1 ("sin" (𝝅/𝟐 βˆ’πŸ‘π›‘/πŸ“)) = sinβˆ’1 ("sin" ((5πœ‹ βˆ’ 6πœ‹)/10 )) = sinβˆ’1 ("sin" ((βˆ’π…)/𝟏𝟎 )) Let y = sinβˆ’1 ("sin" ((βˆ’πœ‹)/10 )) sin y = "sin" ((βˆ’πœ‹)/10 ) sin y = sin (-18Β°) Hence, y = (βˆ’π…)/𝟏𝟎 Which is in the range of sin-1 i.e. [(βˆ’π›‘)/𝟐, 𝛑/𝟐] Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎 Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎

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