CBSE Class 12 Sample Paper for 2024 Boards

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Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at April 16, 2024 by

Find the value of γ€–sinγ€—^(-1) [cos(33π/5)]

This question is similar to Example-9 Chapter-2 Inverse trigonometry

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Transcript

sinβˆ’1 ("cos " 33Ο€/6) = sinβˆ’1 ("cos " (πŸ”π…+πŸ‘π…/πŸ“)) = sinβˆ’1 ("cos " 3πœ‹/5) = sinβˆ’1 ("sin" (𝝅/𝟐 βˆ’πŸ‘π›‘/πŸ“)) = sinβˆ’1 ("sin" ((5πœ‹ βˆ’ 6πœ‹)/10 )) = sinβˆ’1 ("sin" ((βˆ’π…)/𝟏𝟎 )) Let y = sinβˆ’1 ("sin" ((βˆ’πœ‹)/10 )) sin y = "sin" ((βˆ’πœ‹)/10 ) sin y = sin (-18Β°) Hence, y = (βˆ’π…)/𝟏𝟎 Which is in the range of sin-1 i.e. [(βˆ’π›‘)/𝟐, 𝛑/𝟐] Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎 Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo