ASSERTION (A) : The relation f:{1,2,3,4}→{x,y,z,p} defined by f={(1,x),(2,y),(3,z)} is a bijective function.

REASON (R) : The function f:{1,2,3}→{x,y,z,p} such that f={(1,x),(2,y),(3,z)} is one-one.

Ā 

(a) Both A and R are true and R is the correct explanation of A.

(b) Both A and R are true but R is not the correct explanation of A.

(c) A is true but R is false.

(d) A is false but R is true.

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ASSERTION (A): The relation f : {1, 2, 3, 4} → {x,y,z,p} defined by f - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 20 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 20 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 4 - Question 20 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

Checking Assertion ASSERTION (A): The relation š‘“:{1,2,3,4}→{š‘„,š‘¦,š‘§,š‘} defined by š‘“={(1,š‘„),(2,š‘¦),(3,š‘§)} is a bijective function. Making the diagram for the relation We know that, A relation is a function if every element of first set has an image. In this case element 4 has no image Hence, the given relation is not a function Thus, given relation is not a bijective function So, Assertion is false. Checking Reason REASON (R): The function š‘“:{1,2,3}→{š‘„,š‘¦,š‘§,š‘} such that š‘“={(1,š‘„),(2,š‘¦),(3,š‘§)} is one-one. Checking one – one š‘“={(1,š‘„),(2,š‘¦),(3,š‘§)} Since each element has a unique image ∓ f is one-one So, reason is true So, Assertion is false Reasoning is true So, the correct answer is (d)

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