Question 26 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 12, 2026 by Teachoo

Find ∫dx/√3 - 2x - x ²

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Question 26 Find ∫1▒𝑑𝑥/√(3 − 2𝑥 − 𝑥^2 ) ∫1▒𝑑𝑥/√(3 − 2𝑥 − 𝑥^2 ) = ∫1▒〖1/√(−(𝒙^𝟐 + 𝟐𝒙 − 𝟑) ) 𝑑𝑥〗 = ∫1▒〖1/√(−(𝑥^2 + 2𝑥 − 3 + 𝟒 − 𝟒) ) 𝑑𝑥〗 = ∫1▒〖1/√(−(𝑥^2 + 2𝑥 + 1 − 𝟒) ) 𝑑𝑥〗 = ∫1▒〖1/√(−(𝑥^2 + 2𝑥 + 1) + 𝟒) 𝑑𝑥〗 = ∫1▒〖1/√(4 − (𝑥^2 + 2𝑥 + 1) ) 𝑑𝑥〗 = ∫1▒〖1/√(2^2 − (𝑥 + 1)^2 ) 𝑑𝑥〗 = 〖𝒔𝒊𝒏〗^(−𝟏)⁡〖((𝒙 + 𝟏)/𝟐)+𝑪〗

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