The scalar projection of the vector 3i ฬ‚-j ฬ‚-2k ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ i ฬ‚+2j ฬ‚-3k ฬ‚ is

(a) 7/โˆš14 ย 

(b) 7/14 ย 

(c) 6/13 ย 

(d) 7/2

ย 

[MCQ] The scalar projection of vector 3i - j - 2k on vector i+2j-3k is - CBSE Class 12 Sample Paper for 2023 Boards

part 2 - Question 8 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 8 The scalar projection of the vector 3๐‘– ฬ‚โˆ’๐‘— ฬ‚โˆ’2๐‘˜ ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ ๐‘– ฬ‚+2๐‘— ฬ‚โˆ’3๐‘˜ ฬ‚ is (a) 7/โˆš14 (b) 7/14 (c) 6/13 (d) 7/2 Let a = 3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ and b = ๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚ We need to find Projection of ๐‘Ž โƒ— on ๐‘ โƒ— We know that Projection of ๐‘Ž โƒ— on ๐‘ โƒ— = ๐Ÿ/("|" ๐’ƒ โƒ—"|" ) (๐’‚ โƒ—. ๐’ƒ โƒ—) Now, (๐’‚ โƒ—. ๐’ƒ โƒ—) = (3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ ) . (๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚) = (3 ร— 1) + (โ€“1 ร— 2) + (โˆ’2 ร— โˆ’3) = 7 Magnitude of ๐‘ โƒ— = โˆš(12+22+(โˆ’3) 2) |๐’ƒ โƒ— | = โˆš(1+4+9) = โˆš๐Ÿ๐Ÿ’ Thus, Projection of ๐’‚ โƒ— on ๐’ƒ โƒ— = 1/("|" ๐‘ โƒ—"|" ) (๐‘Ž โƒ—. ๐‘ โƒ—) = ๐Ÿ•/โˆš๐Ÿ๐Ÿ’ So, the correct answer is (a)

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