If š¦ = sin -1 x, then (1-x 2 ) y 2 šš equal to
(a) xy 1 Ā
(b) š„š¦Ā
(c) xy 2 Ā
(d) x 2
Ā
CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at August 12, 2026 by Teachoo
Ā
Transcript
Question 16 If š¦ = ćš ššć^(ā1) š„, then (1āš„^2 ) š¦_2 šš equal to (a) ćš„š¦ć_1 (b) š„š¦ (c) ćš„š¦ć_2 (d) š„^2 Given š¦ = ćš ššć^(ā1) š„ Differentiating w.r.t x šš¦/šš„=š(sin^(ā1)ā”š„ )/š„ š š/š š=š/ā(š ā š^š ) š¦^ā²=1/ā(1 ā š„^2 ) š^ā² Ć ā(š ā š^š )=š Again differentiating w.r.t x (š¦^ā² Ć ā(1 ā š„^2 ))^ā²=š(1)/šš„ (š¦^ā² Ć ā(1 ā š„^2 ))^ā²=0 ćš^ā²ā² ā(š ā š^š )+š^ā² (ā(š ā š^š ))ć^ā²=š 暦^ā²ā² ā(1 ā š„^2 )+š¦^ā² Ć1/(2ā(1 ā š„^2 )) (1 ā š„^2 )ć^ā²=0 š¦^ā²ā² ā(1 ā š„^2 )+š¦^ā² Ć1/(2ā(1 ā š„^2 )) Ć ā2š„=0 š¦^ā²ā² ā(1 ā š„^2 )āš¦^ā² Ćš„/ā(1 ā š„^2 ) =0 š¦^ā²ā² ā(1 ā š„^2 )=š¦^ā² Ćš„/ā(1 ā š„^2 ) š¦^ā²ā² ā(1 ā š„^2 ) Ćā(1 ā š„^2 )=š¦^ā² š„ š^ā²ā² (š ā š^š) =š^ā² š So, the correct answer is (a)