If y√1-x 2 +x√1-y 2 =1, then prove that dy/dx=-√1 - y 2 /1 - x 2

[Class 12 Sample Paper] If y√1-x^2 + x√1-y^2, then prove that dy/dx = - CBSE Class 12 Sample Paper for 2023 Boards
part 2 - Question 24 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 24 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 24 If π‘¦βˆš(1βˆ’π‘₯^2 )+π‘₯√(1βˆ’π‘¦^2 )=1, then prove that dy/dx=βˆ’βˆš((1 βˆ’ 𝑦^2)/(1 βˆ’ π‘₯^2 )) Finding π’…π’š/𝒅𝒙 would be complicated here To make life easy, we substitute x = sin A y = sin B (As √(1βˆ’π‘₯^2 )= √(1βˆ’sin^2⁑𝐴 )=√(cos^2⁑𝐴 )) And then solve Let’s substitute x = sin A y = sin B in our equation Now π‘¦βˆš(1βˆ’π‘₯^2 ) + π‘₯√(1βˆ’π‘¦^2 ) = 1 Putting x = sin A and y = sin B 𝐬𝐒𝐧 𝐁√(πŸβˆ’γ€–π¬π’π§γ€—^πŸβ‘π‘¨ ) + 𝐬𝐒𝐧 π€βˆš(πŸβˆ’γ€–π’”π’Šπ’γ€—^πŸβ‘π‘© ) = 1 sin B√(cos^2⁑𝐴 ) + sin A√(cos^2⁑𝐡 ) = a (sin A βˆ’ sin B) sin B cos A + sin A cos B = 1 sin A cos B + sin B cos A = 1 sin (A + B) = 1 sin (A + B) = sin 𝝅/𝟐 A + B = 𝝅/𝟐 Putting back values of A and B sin^(βˆ’1)⁑π‘₯+sin^(βˆ’1)⁑𝑦=πœ‹/2 Differentiating w.r.t x 1/√(1 βˆ’ π‘₯^2 )βˆ’1/√(1 βˆ’ 𝑦^2 )×𝑑𝑦/𝑑π‘₯=0 1/√(1 βˆ’ π‘₯^2 )=1/√(1 βˆ’ 𝑦^2 )×𝑑𝑦/𝑑π‘₯ √(1 βˆ’ 𝑦^2 )/√(1 βˆ’ π‘₯^2 )=𝑑𝑦/𝑑π‘₯ π’…π’š/(𝒅𝒙 ) = √(𝟏 βˆ’ π’š^𝟐 )/√(𝟏 βˆ’ 𝒙^𝟐 )

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