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If 6 is the critical point of the function, then find the value of the constant m.

 

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Question 36 (ii) If 6 is the critical point of the function, then find the value of the constant m.Since 6 is the critical point of the function ∴ f’(6) = 0 Finding f’(x) 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98 Differentiating w.r.t. x 𝑓‘(𝑥) = −0.1 × 2𝑥 + 𝑚 Putting x = 6 𝑓‘(6) = −0.1 × 2 × 6 + 𝑚 0 = −1.2 + m 1.2 = m m = 1.2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.