Given a non-empty set X, define the relation R in P(X) as follows: For A, B ā š(š), (š“, šµ) ā š iff š“ ā šµ. Prove that R is reflexive, transitive and not symmetric.
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CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at August 2, 2026 by Teachoo
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Question 33 (Choice 2) - Introduction Given a non-empty set X, define the relation R in P(X) as follows: For A, B ā š(š), (š“, šµ) ā š iff š“ ā šµ. Prove that R is reflexive, transitive and not symmetric.Taking an example Let X = {1, 2, 3} P(X) = Power set of X = Set of all subsets of X = { š, {1} , {2} , {3}, {1, 2} , {2, 3} , {1, 3}, {1, 2, 3} } Since {1} ā {1, 2} ā“ {1} R {1, 2} Question 33 (Choice 2) Given a non-empty set X, define the relation R in P(X) as follows: For A, B ā š(š), (š“, šµ) ā š iff š“ ā šµ. Prove that R is reflexive, transitive and not symmetric.ARB means A ā B Here, relation is R = {(A, B): A & B are sets, A ā B} Check reflexive Since every set is a subset of itself, A ā A ā“ (A, A) ā R. ā“R is reflexive. Check symmetric To check whether symmetric or not, If (A, B) ā R, then (B, A) ā R If (A, B) ā R, A ā B. But, B ā A is not true Example: Let A = {1} and B = {1, 2}, As all elements of A are in B, A ā B But all elements of B are not in A (as 2 is not in A), So B ā A is not true ā“ R is not symmetric. Checking transitive Since (A, B) ā R & (B, C) ā R If, A ā B and B ā C. then A ā C ā (A, C) ā R So, If (A, B) ā R & (B, C) ā R , then (A, C) ā R ā“ R is transitive. Hence, R is reflexive and transitive but not symmetric.