Prove that the function f is surjective, where š‘“: š‘ → š‘ such that

Ā f(n)={(n + 1)/2,Ā  if n is odd n/2, Ā if n is even

Ā 

Is the function injective? Justify your answer.

[Sample Paper Class 12] Prove that the function f is surjective, where - CBSE Class 12 Sample Paper for 2023 Boards

part 2 - Question 21 (Choice 2) - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 21 (Choice 2) - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

Remove Ads
Teachoo Ā· Class 12 Explore Class 12

Transcript

Question 21 (Choice 2) Prove that the function f is surjective, where š‘“: š‘ → š‘ such that š‘“(š‘›)={ā–ˆ((š‘› + 1)/2, š‘–š‘“ š‘› š‘–š‘  š‘œš‘‘š‘‘@&š‘›/2, š‘–š‘“ š‘› š‘–š‘  š‘’š‘£š‘’š‘›)┤ Is the function injective? Justify your answer. Check onto (surjective) f (n) = {ā–ˆ((š‘› + 1)/2 ", if n is odd" @š‘›/2 ", if n is even" )┤ for all n ∈ N Let f(x) = y , such that y ∈ N When n is odd y = (š‘› + 1)/2 2y = n + 1 2y – 1 = n n = 2y – 1 Hence, for y is a natural number , n = 2y – 1 is also a natural number When n is even y = š‘›/2 2y = n n = 2y Hence for y is a natural number , n = 2y is also a natural number Thus, for every y ∈ N, there exists x ∈ N such that f(n) = y Hence, f is onto (surjective) Check one-one (injective) f (n) = {ā–ˆ((š‘› + 1)/2 ", if n is odd" @š‘›/2 ", if n is even" )┤ for all n ∈ N. f(1) = (1 + 1)/2 = 2/2 = 1 f(2) = 2/2 = 1 Since, f(1) = f(2) but 1 ≠ 2 Both f(1) & f(2) have same image 1 ∓ f is not one-one (not injective)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.