Question 36 [Case Based] The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98, 0 ≤𝑥≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x daysBased on the above information answer the following questions.
Question 36 (i) Is the function differentiable in the interval (0, 12)? Justify your answer.In interval (0, 12)
The function is
𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98
Since it is a polynomial function
And polynomial functions are differentiable everywhere
∴ f(x) is differentiable in (0, 12)
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
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