The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1x^2 + 𝑚𝑥 + 98, 0 ≤x≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x days

Question 36 Class 12 - Teachoo.jpg

Based on the above information answer the following questions.

Question 36 ( i )

Is the function differentiable in the interval (0, 12)? Justify your answer.

 

Slide32.JPG

Slide33.JPG

 


Transcript

Question 36 [Case Based] The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98, 0 ≤𝑥≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x daysBased on the above information answer the following questions. Question 36 (i) Is the function differentiable in the interval (0, 12)? Justify your answer.In interval (0, 12) The function is 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98 Since it is a polynomial function And polynomial functions are differentiable everywhere ∴ f(x) is differentiable in (0, 12)

Go Ad-free
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.