Find the value of sin -1 [sin(13π/7)]
CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at April 16, 2024 by Teachoo
Question 21 (Choice 1) Find the value of γπ ππγ^(β1) [π ππ(13π/7)]. Let y = sinβ1 ("sin " 13Ο/7) sin y = sin (13Ο/7) sin y = sin (334Β°) But, Range of sinβ1 is [(βΟ)/2, Ο/2] i.e. [β90Β° ,90Β° ] Hence, y = 334Β° not possible Now, sin y = sin (13Ο/7) sin y = sin (ππ βπ/π) sin y = β sin (π/π) sin y = sin ((βπ)/π) Hence, y = (βπ )/π Which is in the range of sin-1 i.e. [(βΟ)/2, Ο/2] Hence, sin-1("sin " 13Ο/7) = y = (βπ )/π