Find the value of sin ^{ -1 } [sin(13π/7)]
CBSE Class 12 Sample Paper for 2023 Boards
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CBSE Class 12 Sample Paper for 2023 Boards
Last updated at April 16, 2024 by Teachoo
Question 21 (Choice 1) Find the value of γπ ππγ^(β1) [π ππ(13π/7)]. Let y = sinβ1 ("sin " 13Ο/7) sin y = sin (13Ο/7) sin y = sin (334Β°) But, Range of sinβ1 is [(βΟ)/2, Ο/2] i.e. [β90Β° ,90Β° ] Hence, y = 334Β° not possible Now, sin y = sin (13Ο/7) sin y = sin (ππ βπ/π) sin y = β sin (π/π) sin y = sin ((βπ)/π) Hence, y = (βπ )/π Which is in the range of sin-1 i.e. [(βΟ)/2, Ο/2] Hence, sin-1("sin " 13Ο/7) = y = (βπ )/π