The general solution of the differential equation π¦ππ₯ β π₯ππ¦ = 0 ππ
(a) π₯π¦ = πΆ Β
(b) π₯ = Cy 2 Β
(c) π¦ = πΆπ₯ Β
(d) π¦ = Cx 2
Β
This question is Similar to Misc-16 - Class-12 Miscellaneous
CBSE Class 12 Sample Paper for 2023 Boards
CBSE Class 12 Sample Paper for 2023 Boards
Last updated at Dec. 13, 2024 by Teachoo
Β
This question is Similar to Misc-16 - Class-12 Miscellaneous
Transcript
Question 15 The general solution of the differential equation π¦ππ₯ β π₯ππ¦ = 0 ππ (a) π₯π¦ = πΆ (b) π₯ = γπΆπ¦γ^2 (c) π¦ = πΆπ₯ (d) π¦ = Cπ₯^2π¦ ππ₯ β π₯ ππ¦=0 π¦ ππ₯= π₯ ππ¦ π π/π = π π/π Integrating both sides. β«1βγ(ππ₯ )/π₯=(ππ¦ )/(π¦ )γ log x = log y + C log x β log y = C log ((π )/π) = C (π )/π = c1 y = π₯/π_1 y = Cx So, the correct answer is (c)