Question 26
The maximum value of sin x . cos x is
(A) 1/4 (B) 1/2
(C) β2 (D) 2 β2
Let f(π)=sinβ‘π₯βcosβ‘π₯
=(2 sinβ‘π₯ cosβ‘π₯)/2
=(πππ ππ)/π
Since,
βπβ€πππ π½β€π
Putting π=2π₯
β1β€sinβ‘2π₯β€1
Dividing by 2
β1/2β€(π ππ 2π₯)/2β€1/2
βπ/πβ€π(π)β€π/π
β΄ Maximum value of π(π₯) is π/π.
So, the correct answer is (B).

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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