y = x (x – 3) 2 decreases for the values of x given by :

(A)1 < x < 3 Ā 

(B) x < 0

(C) x > 0 Ā 

(D) 0 < x < 3/2

Ā 

This question is similar to Ex 6.2, 6 - Chapter 6 Class 12 - Application of Derivatives

MCQ Class 12 - y = x (x – 3)2 decreases for the values of x given by : - NCERT Exemplar - MCQs

part 2 - Question 6 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives
part 3 - Question 6 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Transcript

Question 6 y = x (x – 3)2 decreases for the values of x given by : 1 < x < 3 (B) x < 0 (C) x > 0 (D) 0 < x < 3/2 š‘“(š‘„)=š‘„ć€–(š‘„āˆ’3)怗^2 Calculating f’(š’™) f’(š‘„) = (š‘„āˆ’3)^2+š‘„Ć—2(š‘„āˆ’3) f’(š‘„) = (š‘„āˆ’3) [(š‘„āˆ’3)+2š‘„] f’(š‘„) = (š‘„āˆ’3) (3š‘„āˆ’3) f’(š‘„) = (š‘„āˆ’3) Ɨ3(š‘„āˆ’1) f’(š’™) = šŸ‘(š’™āˆ’šŸ‘) (š’™āˆ’šŸ) Putting f’(š’™) = 0 3(š‘„āˆ’3) (š‘„āˆ’1)=0 So, š’™ = 3 , 1 Plotting points on number line Hence, f is decreasing for the šŸ<š’™<šŸ‘. So, the correct answer is (A)

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